How do you integrate $\int \frac{4 x}{x^{4} + 1}$ $int(4x)/(x^4 +1)$ using partial fractions?

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Answer 1 · 2018-06-23T12:43:43

$2 arctan (x^{2}) + c$ $2arctan(x^2) +c$

I believe that you can't use partial fractions because $Delta<0$ and you can't decompose the denominator

Use this immediate integral: $int(f'(x))/(1+[f(x)]^2) = arctan[f(x)] + c$

Write your integral in this way: $2int(2x)/(1+[(x^2)]^2)$

So the result is: $2arctan(x^2) +c$

How do you integrate int(4x)/(x^4 +1) ∫4xx4+1int(4x)/(x^4 +1) using partial fractions?