How do you integrate $\int \frac{x + 1}{(4 x - 5) (x + 3) (x + 4)}$ $int(x+1)/((4x-5)(x+3)(x+4))$ using partial fractions?

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Answer 1 · 2016-10-07T05:32:53

$\frac{3}{119} ln | 4 x - 5 | + \frac{2}{17} ln | x + 3 | - \frac{1}{7} ln | x + 4 | + C$ $3/119 ln |4x - 5| + 2/17 ln |x + 3| - 1/7 ln |x + 4| + C$

That's what I have found! Feel free to correct me if I'm wrong!
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How do you integrate ∫x+1(4x−5)(x+3)(x+4)int(x+1)/((4x-5)(x+3)(x+4)) using partial fractions?