How do you multiply $(12 - 2 i) (3 - 2 i)$ $(12-2i)(3-2i)$ in trigonometric form?

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Answer 1 · 2018-05-26T10:37:46

$- 30 i + 32$ $-30i+32$

$(12 - 2 i) (3 - 2 i)$ $(12-2i)(3-2i)$

$(12 \times 3) - (12 \times 2 i) - (2 i \times 3) + (2 i \times 2 i)$ $(12xx3)-(12xx2i)-(2ixx3)+(2ixx2i)$

$36 - 24 i - 6 i - 4$ $36-24i-6i-4$

$- 30 i + 32$ $-30i+32$

How do you multiply (12−2i)(3−2i) (12-2i)(3-2i) in trigonometric form?