How do you multiply $(- 2 - 9 i) (- 3 - 6 i)$ $(-2-9i)(-3-6i)$ in trigonometric form?

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How do you multiply $(- 2 - 9 i) (- 3 - 6 i)$ $(-2-9i)(-3-6i)$ in trigonometric form?

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Answer 1 · 2016-02-13T10:23:11

-48 +39i

Explanation:

distribute the brackets using FOIL

(-2 -9i )(-3 - 6i) $= 6 + 12 i + 27 i + 54 i^{2}$ $= 6 + 12i + 27i + 54i^2$

[Note : $i^{2} = {(\sqrt{-} 1)}^{2} = - 1$ $i^2 = (sqrt-1)^2 = -1$ ]

hence $6 + 12 i + 27 i + 54 i^{2} = 6 + 39 i - 54 = - 48 + 39 i$ $6+ 12i + 27i + 54i^2 = 6 + 39i - 54 = - 48 + 39i$

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How do you multiply $(- 2 - 9 i) (- 3 - 6 i)$ $(-2-9i)(-3-6i)$ in trigonometric form?

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How do you multiply $(- 2 - 9 i) (- 3 - 6 i)$ $(-2-9i)(-3-6i)$ in trigonometric form?