How do you multiply $(2b^2-2c^2)^2$ ?

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Answer 1 · 2018-04-19T05:37:12

$4b^4-8b^2c+4c^2$

Given -

$(2b^2- 2c)^2$
$(2b^2- 2c)(2b^2- 2c)$

$2b^2(2b^2)-2c(2b^2)+2b^2(-2c)-2c(-2c)$

$4b^4-4b^2c-4b^2c+4c^2$

$4b^4-8b^2c+4c^2$

How do you multiply (2b^2-2c^2)^2(2b^2-2c^2)^2?