How do you multiply ${(2 x - 6 y)}^{2}$ $(2x-6y)^2$ ?

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Answer 1 · 2016-12-22T17:30:50

$4 x^{2} - 24 x y + 36 y^{2}$ $4x^2 -24xy+36y^2$

${(2 x - 6 y)}^{2} = (2 x - 6 y) (2 x - 6 y) = 2 x (2 x - 6 y) - 6 y (2 x - 6 y)$ $(2x-6y)^2 = (2x-6y)(2x-6y) = 2x(2x-6y)-6y(2x-6y)$

= $4 x^{2} - 12 x y - 12 x y + 36 y^{2}$ $4x^2 -12xy -12xy+36y^2$

= $4 x^{2} - 24 x y + 36 y^{2}$ $4x^2 -24xy+36y^2$

How do you multiply (2x−6y)2(2x-6y)^2?