How do you multiply $(4x^2-4y^2)^2$ ?

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Answer 1 · 2016-08-28T13:54:31

$=16x^4+16y^4-32x^2y^2$

$(a-b)^2=a^2+b^2-2ab$

Similarly

$(4x^2-4y^2)^2$

$=(4x^2)^2+(4y^2)^2-2times4x^2times4y^2$

$=16x^4+16y^4-32x^2y^2$

How do you multiply (4x^2-4y^2)^2(4x^2-4y^2)^2?