How do you multiply $(5 - 12 i) (2 + 3 i)$ $(5-12i)(2+3i)$ in trigonometric form?

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How do you multiply $(5 - 12 i) (2 + 3 i)$ $(5-12i)(2+3i)$ in trigonometric form?

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Answer 1 · 2016-11-20T17:48:20

$= 46 - 19 i$ $=46-19i$

Explanation:

Expanding these factors is determined by applying Distributive property.
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Distributive Property:
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$(a + b) (c + d) = a \times c + a \times d + b \times c + b \times d$ $color(blue)((a+b)(c+d) = axxc + axxd + bxxc + bxxd)$
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$(5 - 12 i) (2 + 3 i)$ $(5 - 12i)(2 + 3i)$
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$= 5 \times 2 + 5 \times 3 i + (- 12 i) \times 2 + (- 12 i \times 3 i)$ $=color(blue)(5xx2 + 5xx3i +(-12i)xx2 + (-12ixx3i))$
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$= 10 + 5 i - 24 i - 36 i^{2}$ $=10 + 5i -24i -36i^2$
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$= 10 - 19 i - 36 \times - 1$ $=10 -19i-36xx-1" "$ As we know $i^{2} = - 1$ $" "i^2=-1$
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$= 10 - 19 i + 36$ $=10-19i+36$
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$= 46 - 19 i$ $=46-19i$

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How do you multiply $(5 - 12 i) (2 + 3 i)$ $(5-12i)(2+3i)$ in trigonometric form?

1 Answer

Explanation:

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Math

Humanities

... and beyond

How do you multiply (5−12i)(2+3i) (5-12i)(2+3i) in trigonometric form?

1 Answer

Explanation:

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How do you multiply $(5 - 12 i) (2 + 3 i)$ $(5-12i)(2+3i)$ in trigonometric form?