How do you multiply #(7x-5y)^2#?

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Answer 1 · 2016-09-15T10:38:15

#=49*x^2-70*x*y+25*y^2#

#...............(7x-5y) *(7x-5y)#

#................=49*x^2-35*x*y -35*x*y+25*y^2#

#................=49*x^2-70*x*y+25*y^2#

Answer 2 · 2016-09-15T20:23:57

#49x^2-70xy+25y^2#

Write as: #color(blue)((7x-5y))color(brown)((7x-5y))#

Multiply everything inside the right brackets by everything in the left brackets.

Notice that the minus follows the #color(blue)(-5y)#

#color(brown)(color(blue)(7x)(7x-5y)" "color(blue)(-5y)(7x-5y)) #

#49x^2-35xy" "-35xy+25y^2#

#49x^2-70xy+25y^2#