How do you multiply and simplify (- 3x ^ { 3} y ^ { 4} z ^ { 3} ) ^ { 3} ( 2y z ^ { 2} )? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria Jun 13, 2017 (-3x^3y^4z^3)^3(2yz^2)=-54x^9y^13z^11 Explanation: As (a^m)^n=a^((mxxn)) and a^mxxa^n=a^((m+n)) (-3x^3y^4z^3)^3(2yz^2) = ((-3)^3x^(3xx3)y^(4xx3)z^(3xx3))(2yz^2 = (-27x^9y^12z^9)xx(2yz^2) = (-27)xx2xxx^9y^(12+1)z^(9+2) = -54x^9y^13z^11 Answer link Related questions How do you simplify c^3v^9c^-1c^0? How do you simplify (- 1/5)^-2 + (-2)^-2? How do you simplify (4^6)^2 ? How do you simplify 3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 ? How do you simplify 4^3·4^5? How do you simplify (5^-2)^-3? How do you simplify and write (-5.3)^0 with positive exponents? How do you factor 12j^2k - 36j^6k^6 + 12j^2? How do you simplify the expression 2^5/(2^3 times 2^8)? When can I add exponents? See all questions in Exponents Impact of this question 2702 views around the world You can reuse this answer Creative Commons License