How do you multiply $e^{\frac{13 π}{12}} \cdot e^{\frac{π}{2} i}$ $e^(( 13pi )/ 12 ) * e^( pi/2 i )$ in trigonometric form?

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Answer 1 · 2016-01-06T14:28:30

$e^{\frac{13 π}{2}} ∠ \frac{13 π}{2}$ $e^((13pi)/2)/_(13pi)/2$

From Euler's formula we get that

$e^{i (\frac{π}{2})} = cos (\frac{π}{2}) + i sin (\frac{π}{2}) = i$ $e^(i(pi/2))=cos(pi/2)+isin(pi/2)=i$ .

$therefore e^((13pi)/2)*e^(i(pi/2))=ie^((13pi)/2$

$=e^((13pi)/2)/_(13pi)/2$

How do you multiply e^(( 13pi )/ 12 ) * e^( pi/2 i ) e13π12⋅eπ2ie^(( 13pi )/ 12 ) * e^( pi/2 i ) in trigonometric form?