How do you multiply $e^{\frac{23 π}{12}} \cdot e^{\frac{π}{4} i}$ $e^((23 pi )/ 12 ) * e^( pi/4 i )$ in trigonometric form?

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Answer 1 · 2018-01-26T12:59:41

$a^{b} + a^{c}$ $a^b+a^c$ is always $a^{b + c}$ $a^(b+c)$ :

$e^((23π)/12)⋅e^(πi/4)$

$e^(((23π)/12+π/4i))$

$e^(((23π)/12+3π/12i))$

$e^((23π+3πi)/12)$

How do you multiply e^((23 pi )/ 12 ) * e^( pi/4 i ) e23π12⋅eπ4ie^((23 pi )/ 12 ) * e^( pi/4 i ) in trigonometric form?