How do you multiply #(t^2+5t)/(t+1)div(t+5)#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer MathFact-orials.blogspot.com Feb 26, 2017 #t/(t+1)# Explanation: With the statement #(t^2+5t)/(t+1) -: (t+5)#, let's first see that we can factor the numerator on the left-hand side. The other thing to notice is that when we have something in the form of #a/b -: c/d#, it can be restated as #a/b xx d/c#, and so: #(t^2+5t)/(t+1) -: (t+5)/1# #(t(t+5))/(t+1) xx 1/(t+5)# And now we can cancel: #(t(cancel(t+5)))/(t+1) xx 1/cancel(t+5)# #t/(t+1)# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1488 views around the world You can reuse this answer Creative Commons License