How do you multiply ${(x^{2} - 7 y)}^{2}$ $(x^2-7y)^2$ ?

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Answer 1 · 2016-11-07T15:21:49

#x^4 - 14yx^2 + 49y^2

${(x^{2} - 7 y)}^{2} \Rightarrow$ $(x^2 - 7y)^2 =>$

$(x^{2} - 7 y) (x^{2} - 7 y) \Rightarrow$ $(x^2 - 7y)(x^2 - 7y) =>$

$x^{2} x^{2} - x^{2} (7 y) - x^{2} (7 y) + 7 y 7 y \Rightarrow$ $x^2x^2 - x^2(7y) - x^2(7y) + 7y7y =>$

$x^{4} - 2 \cdot (7 y x^{2}) + 49 y^{2} \Rightarrow$ $x^4 - 2*(7yx^2) + 49y^2 =>$

$x^{4} - 14 y x^{2} + 49 y^{2}$ $x^4 - 14yx^2 + 49y^2$

How do you multiply (x2−7y)2(x^2-7y)^2?