How do you multiply #(x^2-7y)^2#? Algebra Polynomials and Factoring Special Products of Polynomials 1 Answer smendyka Nov 7, 2016 #x^4 - 14yx^2 + 49y^2 Explanation: #(x^2 - 7y)^2 =># #(x^2 - 7y)(x^2 - 7y) =># #x^2x^2 - x^2(7y) - x^2(7y) + 7y7y =># #x^4 - 2*(7yx^2) + 49y^2 =># #x^4 - 14yx^2 + 49y^2# Answer link Related questions What are the Special Products of Polynomials? What is a perfect square binomial and how do you find the product? How do you simplify by multiplying #(x+10)^2#? How do you use the special product for squaring binomials to multiply #(1/4t+2 )^2#? How do you use the special product of a sum and difference to multiply #(3x^2+2)(3x^2-2)#? How do you evaluate #56^2# using special products? How do you multiply #(3x-2y)^2#? How do you factor # -8x^2 +32#? How do you factor #x^3-8y^3#? How do you factor # x^3 - 1#? See all questions in Special Products of Polynomials Impact of this question 1799 views around the world You can reuse this answer Creative Commons License