How do you order the following from least to greatest $\frac{3}{7}, \frac{\sqrt{1}}{\sqrt{2}}, 0.46, \frac{\sqrt{5}}{6}$ $3/7, sqrt1/sqrt2, 0.46, sqrt5/6$ ?

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How do you order the following from least to greatest $\frac{3}{7}, \frac{\sqrt{1}}{\sqrt{2}}, 0.46, \frac{\sqrt{5}}{6}$ $3/7, sqrt1/sqrt2, 0.46, sqrt5/6$ ?

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Answer 1 · 2016-08-05T19:34:21

$\frac{\sqrt{5}}{6}, \frac{3}{7}, 0.46, \sqrt{\frac{1}{2}}$ $sqrt5/6,3/7,0.46,sqrt(1/2)$

Explanation:

$\frac{3}{7} = 0.428, \sqrt{\frac{1}{2}} = 0.707, 0.46, \frac{\sqrt{5}}{6} = 0.373$ $3/7=0.428,sqrt(1/2)=0.707,0.46,sqrt5/6=0.373$
So from least to greatest
$\frac{\sqrt{5}}{6}, \frac{3}{7}, 0.46, \sqrt{\frac{1}{2}}$ $sqrt5/6,3/7,0.46,sqrt(1/2)$

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How do you order the following from least to greatest $\frac{3}{7}, \frac{\sqrt{1}}{\sqrt{2}}, 0.46, \frac{\sqrt{5}}{6}$ $3/7, sqrt1/sqrt2, 0.46, sqrt5/6$ ?

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