How do you order the following from least to greatest $-sqrt1, 0.1, sqrt13, -3/5, sqrt6$ ?

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Answer 1 · 2017-04-23T02:34:50

$-sqrt(1), -3/5, 0.1, sqrt(6), sqrt(13)$

Negative numbers are the smallest, so we need to pick between $-sqrt(1) = -1, " and "-3/5 = -.6$ .

Since $-5/5 = -1, -3/5 " must be greater than " -1$

Since $sqrt(1) = 1, 0.1 < sqrt(1) < sqrt(6) < sqrt(13)$

Also,

$sqrt(4) = 2$ so $sqrt(6) > sqrt(4)$

From a calculator $sqrt(6) ~~ 2.4495$

From a calculator $sqrt(13) ~~ 3.61$

So from least to greatest: $-sqrt(1), -3/5, 0.1, sqrt(6), sqrt(13)$

How do you order the following from least to greatest -sqrt1, 0.1, sqrt13, -3/5, sqrt6-sqrt1, 0.1, sqrt13, -3/5, sqrt6?