How do you order the following from least to greatest $sqrt2, 2.1, -sqrt4, 0, -5/2$ ?

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Answer 1 · 2017-05-03T18:59:35

$-5/2, -sqrt4, 0, sqrt2, 2.1$

$sqrt2, 2.1, -sqrt4, 0, -5/2$

ordering these can be done without using a calculator.

first, convert all numbers to square roots:

$sqrt2 = sqrt2$

$2.1 = sqrt(2.1^2) = sqrt(2.1*2.1) = sqrt4.41$

$-sqrt4 = -sqrt4$

$0=sqrt0$

$-5/2 = -sqrt(5^2/2^2) = -sqrt(25/4) = -sqrt6.25$

$sqrt2, sqrt4.41, -sqrt4, sqrt0, -sqrt6.25$

then order them:

$-sqrt4, sqrt0, sqrt2, sqrt4.41, -sqrt6.25$

you can then convert these back to the original numbers:

$-5/2, -sqrt4, 0, sqrt2, 2.1$

How do you order the following from least to greatest sqrt2, 2.1, -sqrt4, 0, -5/2sqrt2, 2.1, -sqrt4, 0, -5/2?