How do you order the following from least to greatest $\sqrt{4}, 1.8, - \sqrt{10}, - \sqrt{\frac{36}{9}}, 5$ $sqrt4, 1.8, -sqrt10, -sqrt(36/9), 5$ ?

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Answer 1 · 2016-07-29T14:31:04

Convert each radical into decimal form so they can be compared to the other numbers.

$\sqrt{4} = 2$ $sqrt(4)=2$
$- \sqrt{10} \approx - 3.162$ $-sqrt(10)~~-3.162$
$- \sqrt{\frac{36}{9}} = - \sqrt{4} = - 2$ $-sqrt(36/9)=-sqrt(4)=-2$

The numbers, in order, are:

$- \sqrt{10}, - \frac{\sqrt{36}}{9}, 1.8, \sqrt{4}, 5$ $-sqrt10, -sqrt36/9, 1.8, sqrt4, 5$

How do you order the following from least to greatest √4,1.8,−√10,−√369,5sqrt4, 1.8, -sqrt10, -sqrt(36/9), 5?