How do you order the following from least to greatest $- \sqrt{5}, \frac{π}{2}, \frac{π}{3}, 4 \frac{5}{8}, \sqrt{18}$ $-sqrt5, pi/2, pi/3, 4 5/8, sqrt18$ ?

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Answer 1 · 2017-03-28T15:24:41

$- \sqrt{5}, \frac{π}{3}, \frac{π}{2}, \sqrt{18}, 4 \frac{5}{8}$ $-sqrt(5), pi/3, pi/2, sqrt(18), 4 5/8$

$- \sqrt{5}$ $-sqrt(5)$ is the only negative number so it is the smallest.

$\frac{1}{3} < \frac{1}{2}$ $1/3 < 1/2$ , so $pi = 3.14159...$ will make $pi/3 ~~ 1$ and $pi/2 ~~ 1.5$

$sqrt(18)$ is close to $sqrt(16) = 4$ , so $sqrt(18) ~~ 4.2$

$5/8 = 0.625$ , so $4 5/8 = 4.625$

How do you order the following from least to greatest -sqrt5, pi/2, pi/3, 4 5/8, sqrt18−√5,π2,π3,458,√18-sqrt5, pi/2, pi/3, 4 5/8, sqrt18?