How do you perform the operation in trigonometric form $\frac{12 (cos 52 + i sin 52)}{3 (cos 110 + i sin 110)}$ $(12(cos52+isin52))/(3(cos110+isin110))$ ?

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How do you perform the operation in trigonometric form $\frac{12 (cos 52 + i sin 52)}{3 (cos 110 + i sin 110)}$ $(12(cos52+isin52))/(3(cos110+isin110))$ ?

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Answer 1 · 2017-06-01T14:45:02

$\frac{12 (cos 52 + i sin 52)}{3 (cos 110 + i sin 110)} = 4 (cos 58 - i sin 58)$ $(12(cos52+isin52))/(3(cos110+isin110))=4(cos58-isin58)$

Explanation:

$\frac{12 (cos 52 + i sin 52)}{3 (cos 110 + i sin 110)}$ $(12(cos52+isin52))/(3(cos110+isin110))$

= $\frac{12 (cos 52 + i sin 52) (cos 110 - i sin 110)}{3 (cos 110 + i sin 110) (cos 110 - i sin 110)}$ $(12(cos52+isin52)(cos110-isin110))/(3(cos110+isin110)(cos110-isin110))$

= $\frac{12 (cos 52 cos 110 + i sin 52 cos 110 - i cos 52 sin 110 - i^{2} sin 52 sin 110)}{3 ({cos}^{2} 110 - i^{2} {sin}^{2} 110)}$ $(12(cos52cos110+isin52cos110-icos52sin110-i^2sin52sin110))/(3(cos^2 110-i^2sin^2 110))$

= $\frac{12 (cos 52 cos 110 + sin 52 sin 110 + i (sin 52 cos 110 - cos 52 sin 110))}{3 ({cos}^{2} 110 + {sin}^{2} 110)}$ $(12(cos52cos110+sin52sin110+i(sin52cos110-cos52sin110)))/(3(cos^2 110+sin^2 110))$

= $\frac{12 (cos (52 - 110) + i sin (52 - 110))}{3 ({cos}^{2} 110 + {sin}^{2} 110)}$ $(12(cos(52-110)+isin(52-110)))/(3(cos^2 110+sin^2 110))$

= $\frac{12 (cos (- 58) + i sin (- 58))}{3}$ $(12(cos(-58)+isin(-58)))/3$

= $4(cos58-isin58)$

Answer 2 · 2017-06-01T18:33:15

$(12(cos52+isin52))/(3(cos110+isin110))=4(cos58-isin58)$

Explanation:

$(12(cos52+isin52))/(3(cos110+isin110))=4xx(cos52+isin52)/(cos110+isin110)$

$cos52+isin52=e^(52i)$

$cos110+isin110=e^(110i)$

$therefore4xx(cos52+isin52)/(cos110+isin110)=4xxe^(52i)/e^(110i)=4e^(-58i)$

$4e^(-58i)=4(cos-58+isin-58)=4(cos58-isin58)$

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How do you perform the operation in trigonometric form $\frac{12 (cos 52 + i sin 52)}{3 (cos 110 + i sin 110)}$ $(12(cos52+isin52))/(3(cos110+isin110))$ ?

2 Answers

Explanation:

Explanation:

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How do you perform the operation in trigonometric form (12(cos52+isin52))/(3(cos110+isin110))12(cos52+isin52)3(cos110+isin110)(12(cos52+isin52))/(3(cos110+isin110))?

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Explanation:

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How do you perform the operation in trigonometric form $\frac{12 (cos 52 + i sin 52)}{3 (cos 110 + i sin 110)}$ $(12(cos52+isin52))/(3(cos110+isin110))$ ?