How do you perform the operation in trigonometric form $\frac{2 (cos 120 + i sin 120)}{4 (cos 40 + i sin 40)}$ $(2(cos120+isin120))/(4(cos40+isin40))$ ?

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How do you perform the operation in trigonometric form $\frac{2 (cos 120 + i sin 120)}{4 (cos 40 + i sin 40)}$ $(2(cos120+isin120))/(4(cos40+isin40))$ ?

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Answer 1 · 2016-09-10T18:14:17

$= (\frac{1}{2}) \cdot (cos 80 + i sin 80)$ $=(1/2)*(cos80+isin80)$

Explanation:

$f (x) = (\frac{1}{2}) \cdot \frac{(cos 120 + i sin 120) (cos 40 - i sin 40)}{(cos 40 + i sin 40) (cos 40 - i sin 40)}$ $f(x)=(1/2)*((cos120+isin120)(cos40-isin40))/((cos40+isin40)(cos40-isin40)$

$= (\frac{1}{2}) \cdot \frac{cos 120 cos 40 - i^{2} sin 120 cos 40 + i cos 40 sin 120 - i sin 40 cos 120}{{(cos 40)}^{2} - i^{2} {(sin 40)}^{2}}$ $=(1/2)*(cos120cos40-i^2sin120cos40+icos40sin120-isin40cos120)/((cos40)^2-i^2(sin40)^2$

$= (\frac{1}{2}) \cdot (cos 80 + i sin 80)$ $=(1/2)*(cos80+isin80)$

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How do you perform the operation in trigonometric form $\frac{2 (cos 120 + i sin 120)}{4 (cos 40 + i sin 40)}$ $(2(cos120+isin120))/(4(cos40+isin40))$ ?

1 Answer

Explanation:

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How do you perform the operation in trigonometric form 2(cos120+isin120)4(cos40+isin40)(2(cos120+isin120))/(4(cos40+isin40))?

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How do you perform the operation in trigonometric form $\frac{2 (cos 120 + i sin 120)}{4 (cos 40 + i sin 40)}$ $(2(cos120+isin120))/(4(cos40+isin40))$ ?