How do you simplify $((2^3 •(2^2)^3)^2 )/ 2$ ?

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Answer 1 · 2016-07-04T06:47:25

$(2^3*(2^2)^3)^2/2=2^17$

We can use here three formulas relating to exponents;

$a^m*a^n=a^((m+n))$ , $a^m/a^n=a^((m-n))$ and $(a^m)^n=a^((mxxn))$

Hence $(2^3*(2^2)^3)^2/2$

= $(2^3*2^((2xx3)))^2/2$

= $(2^3*2^6)^2/2$

= $(2^((3+6)))^2/2$

= $(2^9)^2/2^1$ (as $a=a^1$ )

= $2^((9xx2))/2^1$

= $2^18/2^1$

= $2^((18-1))$

= $2^17$

How do you simplify ((2^3 •(2^2)^3)^2 )/ 2((2^3 •(2^2)^3)^2 )/ 2?