How do you simplify $2^{- 4}$ $2^-4$ ?

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Answer 1 · 2016-06-29T05:45:21

$2^{- 4} = \frac{1}{16}$ $2^(-4)=1/16$

As $a^{m} \div a^{n} = a^{m - n}$ $a^m-:a^n=a^(m-n)$ , if $m = 0$ $m=0$ ,

we have $a^{0} \div a^{n} = a^{0 - n}$ $a^0-:a^n=a^(0-n)$

or $\frac{1}{a^{n}} = a^{- n}$ $1/a^n=a^(-n)$ i.e. $a^{- n} = \frac{1}{a^{n}}$ $a^(-n)=1/a^n$

Hence, $2^{- 4} = \frac{1}{2^{4}} = \frac{1}{2 \times 2 \times 2 \times 2} = \frac{1}{16}$ $2^(-4)=1/2^4=1/(2xx2xx2xx2)=1/16$

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