How do you simplify ${(\frac{2 r^{3} t^{6}}{5 u^{9}})}^{4}$ $((2r^3t^6)/(5u^9))^4$ ?

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Answer 1 · 2017-08-23T04:53:45

${(\frac{2 r^{3} t^{6}}{5 u^{9}})}^{4} = \frac{16 r^{12} t^{24}}{625 u^{36}}$ $((2r^3t^6)/(5u^9))^4=(16r^12t^24)/(625u^36)$

${(\frac{2 r^{3} t^{6}}{5 u^{9}})}^{4}$ $((2r^3t^6)/(5u^9))^4$

= $\frac{2^{4} r^{3 \times 4} t^{6 \times 4}}{5^{4} u^{9 \times 4}}$ $(2^4r^(3xx4)t^(6xx4))/(5^4u^(9xx4))$

= $\frac{16 r^{12} t^{24}}{625 u^{36}}$ $(16r^12t^24)/(625u^36)$

How do you simplify (2r3t65u9)4((2r^3t^6)/(5u^9))^4?