Question

How do you simplify `(a^2+3a)/(a^2-3a-18)` and what are the ecluded values fot he variables?

Answer 1

`=>a/(a-6)`, `a ne 6`

Explanation:

`=>{a^2+3a}/{a^2-3a-18}`

`=>{acancel{(a+3)}}/{(a-6)cancel{(a+3)}}`

`=>a/(a-6)`

From this, we know:

`=>a-6 ne 0`

`=> a ne 6`