How do you simplify $\frac{16 y^{4} z^{4}}{8 y z^{6}}$ $\frac { 16y ^ { 4} z ^ { 4} } { 8y z ^ { 6} }$ ?

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How do you simplify $\frac{16 y^{4} z^{4}}{8 y z^{6}}$ $\frac { 16y ^ { 4} z ^ { 4} } { 8y z ^ { 6} }$ ?

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Answer 1 · 2017-06-15T09:41:05

Follow explanation. $\frac{2 \times y^{3}}{z^{2}}$ $(2timesy^3)/z^2$

Explanation:

You can write down your equation:

$\frac{8 \times 2 \times y \times y^{3} \times z^{4}}{8 \times y \times z^{4} \times z^{2}}$ $(8times2timesytimesy^3timesz^4)/(8timesytimesz^4timesz^2)$

You can see that $y$ $y$ (on the numerator and the denumerator) and $z^{4}$ $z^4$ on both can be cancelled out as well as 8, yielding

$\frac{2 \times y^{3}}{z^{2}}$ $(2timesy^3)/z^2$

This is your answer:

$\frac{2 \times y^{3}}{z^{2}}$ $(2timesy^3)/z^2$

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How do you simplify $\frac{16 y^{4} z^{4}}{8 y z^{6}}$ $\frac { 16y ^ { 4} z ^ { 4} } { 8y z ^ { 6} }$ ?

1 Answer

Explanation:

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How do you simplify $\frac{16 y^{4} z^{4}}{8 y z^{6}}$ $\frac { 16y ^ { 4} z ^ { 4} } { 8y z ^ { 6} }$ ?