How do you simplify $- \frac{28 x y^{0} z^{4}}{14 x^{7} y^{5} z^{4}}$ $-\frac { 28x y ^ { 0} z ^ { 4} } { 14x ^ { 7} y ^ { 5} z ^ { 4} }$ ?

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Answer 1 · 2017-06-15T05:08:54

$\frac{28 x y^{0} z^{4}}{14 x^{7} y^{5} z^{4}} = \frac{2}{x^{6} y^{5}}$ $(28xy^0z^4)/(14x^7y^5z^4)=2/(x^6y^5)$

$\frac{28 x y^{0} z^{4}}{14 x^{7} y^{5} z^{4}}$ $(28xy^0z^4)/(14x^7y^5z^4)$

= $\frac{28}{14} \times \frac{x^{1}}{x^{7}} \times \frac{y^{0}}{y^{5}} \times \frac{z^{4}}{z^{4}}$ $28/14xx x^1/x^7xxy^0/y^5xxz^4/z^4$

= $2 \times x^{(1 - 7)} \times y^{(0 - 5)} \times z^{(4 - 4)}$ $2xx x^((1-7))xxy^((0-5))xxz^((4-4))$

= $2 \times x^{- 6} \times y^{- 5} \times z^{0}$ $2xx x^(-6)xxy^(-5)xxz^0$

= $2 \times \frac{1}{x^{6}} \times \frac{1}{y^{5}} \times 1$ $2xx1/x^6xx1/y^5xx1$

= $\frac{2}{x^{6} y^{5}}$ $2/(x^6y^5)$

How do you simplify -\frac { 28x y ^ { 0} z ^ { 4} } { 14x ^ { 7} y ^ { 5} z ^ { 4} }−28xy0z414x7y5z4-\frac { 28x y ^ { 0} z ^ { 4} } { 14x ^ { 7} y ^ { 5} z ^ { 4} }?