How do you simplify $\frac{{(2 x y^{4})}^{3}}{2 x y^{5} \cdot y x^{5}}$ $\frac { ( 2x y ^ { 4} ) ^ { 3} } { 2x y ^ { 5} \cdot y x ^ { 5} }$ ?

Question

1661 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-24T12:21:10

$\frac{{(2 x y^{4})}^{3}}{2 x y^{5} \cdot y x^{5}} = \frac{4 y^{6}}{x^{3}}$ $(2xy^4)^3/(2xy^5*yx^5)=(4y^6)/x^3$

$\frac{{(2 x y^{4})}^{3}}{2 x y^{5} \cdot y x^{5}}$ $(2xy^4)^3/(2xy^5*yx^5)$

= $\frac{2^{3} \times x^{3} {(y^{4})}^{3}}{2 x^{1 + 5} y^{5 + 1}}$ $(2^3xx x^3(y^4)^3)/(2x^(1+5)y^(5+1))$

= $\frac{8 x^{3} y^{12}}{2 x^{6} y^{6}}$ $(8x^3y^12)/(2x^6y^6)$

= $(cancel8^4y^(12-6))/(cancel2x^(6-3))$

= $(4y^6)/x^3$

How do you simplify \frac { ( 2x y ^ { 4} ) ^ { 3} } { 2x y ^ { 5} \cdot y x ^ { 5} }(2xy4)32xy5⋅yx5\frac { ( 2x y ^ { 4} ) ^ { 3} } { 2x y ^ { 5} \cdot y x ^ { 5} }?