How do you simplify $\frac { ( 4p ^ { 5} r ^ { 3} ) ^ { 2} } { ( 2p ^ { 4} ) ( 3p r ^ { 6} ) }$ ?

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Answer 1 · 2017-07-15T16:42:58

$(4p^5r^3)^2/((2p^4)(3pr^6))=(8p^5)/3$

$(4p^5r^3)^2/((2p^4)(3pr^6))$

= $(4^2(p^5)^2(r^3)^2)/(2xx3xx(p^4xxp)xxr^6)$

= $(16p^(5xx2)r^(3xx2))/(6p^(4+1)r^6)$

= $(16p^10r^6)/(6p^5r^6)$

= $(2xx8p^10r^6)/(2xx3p^5r^6)$

= $(cancel2xx8p^10cancel(r^6))/(cancel2xx3p^5cancel(r^6))$

= $(8p^(10-5))/3$

= $(8p^5)/3$

How do you simplify \frac { ( 4p ^ { 5} r ^ { 3} ) ^ { 2} } { ( 2p ^ { 4} ) ( 3p r ^ { 6} ) }\frac { ( 4p ^ { 5} r ^ { 3} ) ^ { 2} } { ( 2p ^ { 4} ) ( 3p r ^ { 6} ) }?