How do you simplify #(x^2 - 16 )/( 2x^2 - 9x + 4) div (2x^2 + 14x + 24) /( 4x + 4)#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Adrian D. · Stefan V. Aug 9, 2015 #(2(x+1))/((2x-1)(x+3))# Explanation: By factoring note that: #(x^2-16)/(2x^2-9x+4)÷(2x^2+14x+24)/(4x+4)=# #((x+4)(x-4))/((2x-1)(x-4))*(4(x+1))/(2(x+3)(x+4))# Cancel like terms: #(cancel((x+4))cancel((x-4)))/((2x-1)cancel((x-4)))*(cancel(4)color(blue)(2)(x+1))/(cancel(2) (x+3)cancel((x+4)))=# #(2(x+1))/((2x-1)(x+3))# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 2638 views around the world You can reuse this answer Creative Commons License