How do you sketch one cycle of $y=-sin2x$ ?

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Answer 1 · 2017-10-08T19:24:59

$y=sin(2x)$
graph{sin(2x) [-10, 10, -5, 5]}

$y=-sin(2x)$
$x=0,y=0$
$x=pi/4,y=-1$
$x=pi/2,y=0$
$x=(-pi/4),y=1$
With these values, we can plot the graph.

How do you sketch one cycle of y=-sin2xy=-sin2x?