How do you solve $[(20 + 7) \div 3 - 5] \times 7$ $[( 20+ 7) \div 3- 5] \times 7$ ?

Question

2444 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-15T20:55:02

28

Order of doing math operations.
enter image source here

$[27 \div 3 - 5] \times 7$ $[27 divide 3-5] times 7$

$[9 - 5] \times 7$ $[9-5] times 7$

$4 \times 7$ $4 times 7$

$28$ $28$

Answer 2 · 2018-03-15T20:58:12

28

enter image source here

$[(20 + 7) \div 3 - 5] \cdot 7$ $[(20+7)div3-5]*7$

$(20 + 7) = 27$ $(20+7)=27$

$[27 \div 3 - 5] \cdot 7$ $[27div3-5]*7$

$[9 - 5] \cdot 7$ $[9-5]*7$

$[4] \cdot 7$ $[4]*7$

$4 \cdot 7$ $4*7$

$4 \cdot 7 = 28$ $4*7=28$

How do you solve [(20+7)÷3−5]×7[( 20+ 7) \div 3- 5] \times 7?