How do you solve #|2x + -6| ≤ 16#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Narad T. Oct 17, 2016 #-5<=x<=11# Explanation: #∣2x-6∣<=16# then #2x-6<=16# and #-(2x-6)<=16# So #2x<=22# and #-2x+6<=16# #x<=11# and #2x>=-10# the answer is #x<=11# and #x>=-5# #-5<=x<=11# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 3325 views around the world You can reuse this answer Creative Commons License