How do you solve #-33<=-7n-12<-26#?

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Answer 1 · 2016-09-12T15:33:36

# 2< n le 3#.

#"Writing in the Interval Form, "n in (2,3]#.

#-33le-7n-12<-26#.

Adding #12# throughout,

#-33+12le-7n-12+12<-26+12#

#:. -21le-7n<-14#.

Now, to separate #n#, we have to divide the inequality by #-7#, and,

as #-7# is a #-ve# number, the inequality has to be reversed. So,

#-21/-7 ge (-7n)/-7 > -14/-7,# i.e.,

#3ge n> 2#, or what is the same as,

# 2< n le 3#.

#"Writing in the Interval Form, "n in (2,3]#.