How do you solve #abs(3x+2)<7#?
1 Answer
Apr 16, 2017
Explanation:
Inequalities of the type
#|x|< a# always have solutions of the form
#-a < x< a#
#rArr-7 < 3x+2 < 7#
#color(blue)" Isolate " x " in the centre interval"#
#"subtract 2 from ALL three intervals"#
#-7-2 < 3xcancel(+2)cancel(-2)<7-2#
#rArr-9 < 3x < 5#
#"divide ALL three intervals by 3"#
#(-9)/3 < (cancel(3) x)/cancel(3) < 5/3#
#rArr-3 < x < 5/3" is the solution"#
