How do you solve #abs(7x+5)<23#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer VinÃcius Ferraz Apr 20, 2017 #x in (-4, 18/7)# Explanation: By the property: #|a| < b ==> -b < a < b# #-23 < 7x + 5 < 23# #-23 - 5 < 7x < 23 - 5# #-28/7 < x < 18/7# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1241 views around the world You can reuse this answer Creative Commons License