How do you solve #abs(x+2)<= 3#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Alberto M. May 25, 2015 #abs(x+2)<=3 <=> x+2<=3 and -x-2<=3 <=> x<=1 and -x<=5# So, intersecting the two sets of solutions #S={x in RR : -5<=x<=1} = [-5,1]# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1422 views around the world You can reuse this answer Creative Commons License