Question

How do you solve `abs(x+2)-5>=8`?

Answer 1

Solution: `x <= -15 or x >= 11`. In interval notation: `(-oo,-15]uu[11,oo)`

Explanation:

`| x+2| -5 >= 8 or | x+2| >= 8 +5 or x+2 >=13 or x >= 11` OR

`| x+2| -5 >= 8 or | x+2| >= 8 +5 or x+2 <= -13 or x <= -15`

Solution: `x <= -15 or x >= 11`. In interval notation: `(-oo,-15]uu[11,oo)`[Ans]