How do you solve #abs(x/3+1/4)>1/2#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer James Apr 28, 2018 The answer #x>3/4# and #x<-9/4# Explanation: show the steps #|x/3+1/4|>1/2# First sol: #x/3+1/4>1/2# #x/3>1/4# #x>3/4# second sol: #x/3+1/4<-1/2# #x/3<-3/4# #x<-9/4# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1468 views around the world You can reuse this answer Creative Commons License