Question

How do you solve `abs(x+a)>=a`?

Answer 1

Solution: `x>= 0 or x<= -2a` , In interval notation: `(-oo, -2a] uu [0, oo)`

Explanation:

`|x+a| >= a or x+a >= a or x >= a-a or x>= 0` OR

`|x+a| >= a or x+a <= -a or x <= -a-a or x<= -2a`

Solution: `x>= 0 or x<= -2a` , In interval notation: `(-oo, -2a] uu [0, oo)` [Ans]