How do you solve #absx<1+abs1.5#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Alan P. May 7, 2015 Note that #abs(1.5) = 1.5# (taking the absolute value of a positive value has no effect on the value. So #abs(x) <1 +abs(1.5)# is the same as #abs(x) < 2.5# or #-2.5< x< 2.5# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1332 views around the world You can reuse this answer Creative Commons License