How do you solve and graph #abs(4p+2)>=10#?

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Answer 1 · 2018-02-23T11:13:16

#p in (-oo,-3]uu[2,+oo)#

#abs(4p+2)>=10#

Then, either #4p+2 >=+10 or 4p+2 <= -10#

Hence, either #4p>=8 -> p>=2#

or #4p<=12 -> p<=3#

Thus, the solution set for #p# is #(-oo,-3]uu[2,+oo)#

This result can be shown graphically below.

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Where #p# is represented on the vertical axis.