How do you solve $\frac{3}{8} + 2 \frac{1}{2}$ $\frac{3}{8}+2\frac{1}{2}$ ?

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How do you solve $\frac{3}{8} + 2 \frac{1}{2}$ $\frac{3}{8}+2\frac{1}{2}$ ?

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Answer 1 · 2016-10-03T10:26:32

$\frac{3}{8} + \frac{5}{2} = \frac{3}{8} + \frac{5}{2} (\frac{4}{4}) = \frac{3}{8} + \frac{20}{8} = \frac{23}{8}$ $3/8+5/2=3/8+5/2(4/4)=3/8+20/8=23/8$

Explanation:

We have:

$\frac{3}{8} + 2 \frac{1}{2}$ $3/8+2 1/2$

Let's first get the $2 \frac{1}{2}$ $2 1/2$ into a single fraction:

$2 \frac{1}{2} = \frac{5}{2}$ $2 1/2=5/2$

So now we have:

$\frac{3}{8} + 2 \frac{1}{2} = \frac{3}{8} + \frac{5}{2}$ $3/8+2 1/2=3/8+5/2$

Now we need to get the denominators to be the same (this is like making sure when we share slices of pizza with our friends that everyone has the same size slice):

$\frac{3}{8} + \frac{5}{2} = \frac{3}{8} + \frac{5}{2} (\frac{4}{4}) = \frac{3}{8} + \frac{20}{8} = \frac{23}{8}$ $3/8+5/2=3/8+5/2(4/4)=3/8+20/8=23/8$

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How do you solve $\frac{3}{8} + 2 \frac{1}{2}$ $\frac{3}{8}+2\frac{1}{2}$ ?

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