How do you solve the inequality $abs(2x - 5) ≤ 3x$ ?

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Answer 1 · 2016-05-25T07:08:20

$x>=1$ .

As $|2x-5|>=0, 3x>=0$ . So, $x>=0$ .

The inequality $|2x-5|<=3x$ is the combined inequality for

$2x-5<=3x and -(2x-5)<=3x$ ,

So, $x>=-5 and x>=1$ .

Negative x is inadmissible . So, $x>=1$ .

How do you solve the inequality abs(2x - 5) ≤ 3xabs(2x - 5) ≤ 3x?