How do you solve the inequality #abs(7x+2)>10# and write your answer in interval notation? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Binayaka C. Apr 3, 2017 Solution: #x >8/7 or x < -12/7#. In interval notation : #( - oo , -12/7, ) uu ( 8/7 ,oo) # Explanation: #|7 x + 2| > 10 or 7 x+2 > 10 or 7 x > 8 or x >8/7 or x > 1 1/7# OR #|7 x + 2| > 10 or 7 x+2 < -10 or 7 x < -12 or x < -12/7 or x <- 1 5/7# Solution: #x >8/7 or x < -12/7#. In interval notation : #(-oo , -12/7, ) uu ( 8/7 ,oo) # [ANS] Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1330 views around the world You can reuse this answer Creative Commons License