How do you solve this?

Question

What is the perimeter of a rectangle whose length is #7sqrt3+3sqrt5# and whose width is #4sqrt3+2sqrt5# ?

1194 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-27T15:41:58

Perimeter is #22sqrt3+10sqrt5#

Perimeter of a rectangle is double the sum of its length and breadth.

In other words, if #l# is length and #w# is width then perimeter is

#2xx(l+w)#

Hence as length is #7sqrt3+3sqrt5# and width is #4sqrt3+2sqrt5#

Perimeter is #2xx(7sqrt3+3sqrt5+4sqrt3+2sqrt5)#

= #2xx(11sqrt3+5sqrt5)#

= #22sqrt3+10sqrt5#