How do you solve #|x+1|≤8#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Gerardina C. Jul 6, 2016 #-9<=x<=7# Explanation: Since #|f(x)|<=kharr -k<=f(x)<=k#, you have, in this case: #|x+1|<=8 harr -8<=x+1<=8# #-8-1<=x<=8-1# #-9<=x<=7# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1904 views around the world You can reuse this answer Creative Commons License