How do you use partial fraction decomposition to decompose the fraction to integrate $(2x-82)/(x^2+2x-48)$ ?

Question

2022 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-24T04:48:16

$d/dx(x^2+2x-48)=2x+2$

$(2x-82)/(x^2+2x-48) = (2x+2-84)/(x^2+2x-48)$

$(2x-82)/(x^2+2x-48) = (2x+2)/(x^2+2x-48)-(84)/(x^2+2x-48$

By above partial fraction the function can easily be integrated.

How do you use partial fraction decomposition to decompose the fraction to integrate (2x-82)/(x^2+2x-48) (2x-82)/(x^2+2x-48) ?