How do you use the amplitude and period to graph $y= .5 cos^-1 (x-(pi/2))$ ?

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Answer 1 · 2016-06-25T12:02:30

Inversely, $x=pi/2+cos (2y)$ .
Amplitude is 1 and period is $pi$ . The axis of the wave is along $x = pi/2$ .

Data for one full wave:

$(x, y): (pi/2+1, 0) (pi/2+1/sqrt 2, pi/8) (pi/2, pi/4)$

$(pi/2-1/sqrt 2, (3pi)/8) ((pi/2-1, pi/2) (pi/2-1/sqrt 2, (5pi)/8) ((pi/2+1, pi)$ -

How do you use the amplitude and period to graph y= .5 cos^-1 (x-(pi/2))y= .5 cos^-1 (x-(pi/2))?