How do you use transformation to graph the sin function and determine the amplitude and period of $y = - 2 sin x$ $y=-2sinx$ ?

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How do you use transformation to graph the sin function and determine the amplitude and period of $y = - 2 sin x$ $y=-2sinx$ ?

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Answer 1 · 2016-11-02T15:01:09

The period is $2 π$ $2pi$ and the amplitude is $\pm 2$ $+-2$

Explanation:

The amplitude of $sin (x)$ $sin(x)$ is $\pm 1$ $+-1$ so $2 sin (x)$ $2sin(x)$ increases that to $\pm 2$ $+-2$
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If $y_{1} = sin (x)$ $y_1=sin(x)" "$ then $y_{2} = 2 y_{1} = 2 sin (x)$ $" "y_2=2y_1=2sin(x)$
So $y_{2}$ $y_2$ is twice as big as $y_{1}$ $y_1$
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Then by changing $2 sin (x)$ $2sin(x)$ to $- 2 sin (x)$ $-2sin(x)$ what was positive will be negative and what was negative will be positive.

The period does not change. What changes the period is something like $sin (a x)$ $sin(ax)$ where $a$ $a$ is a constant.

The period is $2 π$ $2pi$ and the amplitude is $\pm 2$ $+-2$

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How do you use transformation to graph the sin function and determine the amplitude and period of $y = - 2 sin x$ $y=-2sinx$ ?

1 Answer

Explanation:

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How do you use transformation to graph the sin function and determine the amplitude and period of y=−2sinxy=-2sinx?

1 Answer

Explanation:

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How do you use transformation to graph the sin function and determine the amplitude and period of $y = - 2 sin x$ $y=-2sinx$ ?